16x^2+10-27=-6x+5

Solution for 16x^2+10-27=-6x+5 equation:

16x^2+10-27=-6x+5

We move all terms to the left:

16x^2+10-27-(-6x+5)=0

We add all the numbers together, and all the variables

16x^2-(-6x+5)-17=0

We get rid of parentheses

16x^2+6x-5-17=0

We add all the numbers together, and all the variables

16x^2+6x-22=0

a = 16; b = 6; c = -22;
Δ = b2-4ac
Δ = 62-4·16·(-22)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-38}{2*16}=\frac{-44}{32}
=-1+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+38}{2*16}=\frac{32}{32}
=1
$